RS Aggarwal Solutions for Class 10 Maths Chapter 2 Polynomials = � 24 � 40 + 54 + 10 = 0 f(1/3) = 3 (1/3)^3 � 10(1/3)^2 � 27(1/3) + 10 = 1/9 � 10/9 � 9 + 10 = 0 Verify relations: General form of a cubic equation: ax^3 + bx^2 + cx + d. Now, Consider ? = 5, ? = � 2 and ? = 1/3 ? + ? + ? = 5 � 2 + 1/3 = 10/3 = . ML Aggarwal Solutions for Class 10 Maths Chapter 2 - Consider r% p.a. as the rate of interest Interest = PRT/ Substituting the values = ( ? r ? 1)/ ( ? 12) So we get = r By further calculation r = / = 10 Hence, the rate of interest = 10% p.a. 5. David opened a Recurring Deposit Account in a bank and deposited ? per month for two. NCERT Solutions for Class 10 Science. NCERT Solutions for Class 10 Science Chapter 1; NCERT Solutions for Class 10 Science Chapter 2; NCERT Solutions for Class 10 Science Chapter 3. Final:

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